0=-15x^2+150x

Solution for 0=-15x^2+150x equation:

0=-15x^2+150x

We move all terms to the left:

0-(-15x^2+150x)=0

We add all the numbers together, and all the variables

-(-15x^2+150x)=0

We get rid of parentheses

15x^2-150x=0

a = 15; b = -150; c = 0;
Δ = b2-4ac
Δ = -1502-4·15·0
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-150}{2*15}=\frac{0}{30}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+150}{2*15}=\frac{300}{30}
=10
$